20b^2-11b=3

Solution for 20b^2-11b=3 equation:

Simplifying
20b2 + -11b = 3

Reorder the terms:
-11b + 20b2 = 3

Solving
-11b + 20b2 = 3

Solving for variable 'b'.

Reorder the terms:
-3 + -11b + 20b2 = 3 + -3

Combine like terms: 3 + -3 = 0
-3 + -11b + 20b2 = 0

Factor a trinomial.
(-1 + -5b)(3 + -4b) = 0

Subproblem 1
Set the factor '(-1 + -5b)' equal to zero and attempt to solve:

Simplifying
-1 + -5b = 0

Solving
-1 + -5b = 0

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -5b = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -5b = 0 + 1
-5b = 0 + 1

Combine like terms: 0 + 1 = 1
-5b = 1

Divide each side by '-5'.
b = -0.2

Simplifying
b = -0.2
Subproblem 2
Set the factor '(3 + -4b)' equal to zero and attempt to solve:

Simplifying
3 + -4b = 0

Solving
3 + -4b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -4b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -4b = 0 + -3
-4b = 0 + -3

Combine like terms: 0 + -3 = -3
-4b = -3

Divide each side by '-4'.
b = 0.75

Simplifying
b = 0.75
Solution
b = {-0.2, 0.75}